You are watching: What is the sum of 5 30 4 6

For example, 6 + 9 + 12 + 15 + 18 is a collection for the is the expression for the sum of the terms of the sequence 6, 9, 12, 15, 18.

By the same token, 1 + 2 + 3 + .....100 is a series for that is an expression for the sum of the regards to the succession 1, 2, 3, ......100.

To find the sum of arithmetic series, we have the right to start v an activity.

The arithmetic series formula will make feeling if you understand this activity. Emphasis then a lot on this activity!

## Sum that arithmetic series: exactly how to uncover the amount of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.

Using the succession 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.Add the first and last regards to the sequence and also write down the answer.Then, add the 2nd and next-to-last terms.Continue through the pattern until there is nothing to add.We get:1 + 10 = 112 + 9 = 113 + 8 = 114 + 7 = 115 + 6 = 11 What patterns perform see? The sum is constantly 11.11 + 11 + 11 + 11 + 11 = 5 × 11 = 55 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55As you have the right to see rather of including all the state in the sequence, you deserve to just perform 5 × 11 due to the fact that you will gain the same answer.We can make a generalization that will help us find the sum of arithmetic series.

**Notice the 1 is the an initial term that the sequence. Notification also that 10 is the last term that the sequence.**

n is the number of term, a1 is the very first term, and also an is the nth or last term.You will have actually no problem now to discover the amount of 1 + 2 + 3 + 4 + ... + 100.n = 100, a1 = 1, an = 100

Sn =

100/2

× (1 + 100 )

Sn = 50 × 101 = 5050 discover the amount of the arithmetic series 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 n = 10, a1 = 5, an = 50

Sn =

10/2

× ( 5 + 50 )

Sn = 5 × 55 = 275 Observation:

n is the number of term, a1 is the very first term, and also an is the nth or last term.You will have actually no problem now to discover the amount of 1 + 2 + 3 + 4 + ... + 100.n = 100, a1 = 1, an = 100

Sn =

100/2

× (1 + 100 )

Sn = 50 × 101 = 5050 discover the amount of the arithmetic series 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 n = 10, a1 = 5, an = 50

Sn =

10/2

× ( 5 + 50 )

Sn = 5 × 55 = 275 Observation:

**5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 = 5 × (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)We currently found the sum of 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 above. That is 55. 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 = 5 × 55 = 275**

The typical difference is the samenumber that is included to each term

## How to uncover the variety of terms or n once looking the amount of arithmetic series

When looking for the amount of arithmetic series, that is not constantly easy to recognize the number of terms or n.Just usage the formula listed below to discover n.The typical difference is the same

**How plenty of term here? 2 + 6 + 10 + 14 + ... + 78 common difference is 4**

variety of terms =

78 - 2 /4

+ 1 = 19 + 1 = 20 terms

Summation Notation:

variety of terms =

78 - 2 /4

+ 1 = 19 + 1 = 20 terms

Summation Notation:

**See the summation notation because that the collection 8 + 14 + 20 + 26 + 32 + 38. If you room having hard time to derive the clear formula, testimonial arithmetic sequence. The an approach is explained in arithmetic sequence.**

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As you have the right to see whenn = 1,6 ×1 + 2 = 6 + 2 = 8n = 2, 6 ×2 + 2 = 12 + 2 = 14n = 3, 6 ×3 + 2 = 18 + 2 = 20n = 4, 6 ×4 + 2 = 24 + 2 = 26n = 5, 6 ×5 + 2 = 30 + 2 = 32n = 6, 6 ×6 + 2 = 36 + 2 = 38The large Greek letter that looks like an E is the Greek resources letter sigma. That is the tantamount of the English letter S for summation. Discover the summation notation because that 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50A great observation may assist you watch that 5n is the explicit formula because that 5, 10, 15, 20, 25, 30, 35, 40, 45, 50Why? as soon as n = 1, 5 × 1 = 5, when n = 2, 5 × 2 = 10, and also so forth...The top limit is 10 due to the fact that we have 10 termsThe lower limit is 1$$ S_n = \sum_i=1^10 5n $$

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As you have the right to see whenn = 1,6 ×1 + 2 = 6 + 2 = 8n = 2, 6 ×2 + 2 = 12 + 2 = 14n = 3, 6 ×3 + 2 = 18 + 2 = 20n = 4, 6 ×4 + 2 = 24 + 2 = 26n = 5, 6 ×5 + 2 = 30 + 2 = 32n = 6, 6 ×6 + 2 = 36 + 2 = 38The large Greek letter that looks like an E is the Greek resources letter sigma. That is the tantamount of the English letter S for summation. Discover the summation notation because that 5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50A great observation may assist you watch that 5n is the explicit formula because that 5, 10, 15, 20, 25, 30, 35, 40, 45, 50Why? as soon as n = 1, 5 × 1 = 5, when n = 2, 5 × 2 = 10, and also so forth...The top limit is 10 due to the fact that we have 10 termsThe lower limit is 1$$ S_n = \sum_i=1^10 5n $$

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Arithmetic sequence

Sum the arithmetic series

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