This encounters adding, subtracting and also finding the least common multiple.
You are watching: What is 3/10 of 50
Step by action Solution
Rearrange:Rearrange the equation by subtracting what is come the appropriate of the equal sign from both political parties of the equation : 3/10-(x/50)=0
Step by action solution :
Step 1 :
x leveling —— 50Equation at the end of action 1 : 3 x —— - —— = 0 10 50
Step 2 :3 simplify —— 10Equation at the end of step 2 : 3 x —— - —— = 0 10 50
Step 3 :Calculating the Least usual Multiple :3.1 discover the Least typical Multiple The left denominator is : 10 The appropriate denominator is : 50
|Product that allPrime Factors||10||50||50|
Least common Multiple: 50Calculating multiplier :
3.2 calculation multipliers for the two fractions signify the Least usual Multiple through L.C.M denote the Left Multiplier through Left_M represent the ideal Multiplier by Right_M denote the Left Deniminator through L_Deno represent the ideal Multiplier through R_DenoLeft_M=L.C.M/L_Deno=5Right_M=L.C.M/R_Deno=1Making tantamount Fractions :
3.3 Rewrite the two fractions into indistinguishable fractionsTwo fountain are dubbed equivalent if they have the exact same numeric value. For instance : 1/2 and 2/4 room equivalent, y/(y+1)2 and also (y2+y)/(y+1)3 are identical as well. To calculation equivalent portion , main point the molecule of every fraction, by its respective Multiplier.
L. Mult. • L. Num. 3 • 5 —————————————————— = ————— L.C.M 50 R. Mult. • R.
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Num. X —————————————————— = —— L.C.M 50Adding fountain that have a typical denominator :3.4 adding up the two equivalent fractions add the two equivalent fractions i beg your pardon now have actually a typical denominatorCombine the molecule together, put the sum or difference over the usual denominator then minimize to lowest terms if possible:
3 • 5 - (x) 15 - x ——————————— = —————— 50 50 Equation in ~ the finish of action 3 : 15 - x —————— = 0 50
Step 4 :When a portion equals zero :4.1 as soon as a fraction equals zero ...Where a portion equals zero, its numerator, the part which is over the fraction line, should equal zero.Now,to remove the denominator, Tiger multiplys both sides of the equation by the denominator.Here"s how:
15-x ———— • 50 = 0 • 50 50 Now, on the left hand side, the 50 cancels out the denominator, while, ~ above the ideal hand side, zero times anything is quiet zero.The equation now takes the shape:15-x=0
Solving a single Variable Equation:4.2Solve:-x+15 = 0Subtract 15 indigenous both sides of the equation:-x = -15 multiply both sides of the equation by (-1) : x = 15