The exerted pressure in both instances will it is in same due to the fact that the object is exact same in both scenarios.The only difference is that rebounds energy will be lesser in second case. The reason behind this reduction is that some component of rebounds power will be offered in deforming the shape of the car. Hence, the given statement is true.




You are watching: In a collision a vehicle that rebounds off the object



As we know that bag is stopped because of the force of friction on the table

so below by the offered equation we will certainly say

*

now us have

*

now indigenous the above equation we likewise have

*

now we have

*

*

m = 12 kg

*

now we will certainly have

*

*

so friction pressure will be 21.82 N



usmam.org:

20 seconds.

Explanation:

The complying with data were derived from the question:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

The rate of things is simply defined as the distance travelled by the object every unit time. Mathematically, that is express as:

Speed = distance /time

With the over formula, us can obtain the time taken because that the round to take trip a distance of 10 m as presented below:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

Speed = street /time

0.5 = 10/time

Cross multiply

0.5 × time = 10

Divide both side by 0.5

Time = 10/0.5

Time = 20 secs.

Therefore, it will take 20 secs for the round to travel a distance of 10 m.


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